sin [π/3-sin ^{ (-1) } (-1/2) ] is equal to :
(a) 1/2 (b) 1/3
(c) −1 (d) 1
This question is inspired from Ex 2.2, 20 (MCQ) - Chapter 2 Class 12 - Inverse Trigonometric Functions
Last updated at Sept. 4, 2021 by Teachoo
This question is inspired from Ex 2.2, 20 (MCQ) - Chapter 2 Class 12 - Inverse Trigonometric Functions
Transcript
Question 1 sin [𝜋/3−sin^(−1)(−1/2) ] is equal to : (a) 1/2 (b) 1/3 (c) −1 (d) 1 sin[𝜋/3− 〖𝐬𝐢𝐧〗^(−𝟏)(−𝟏/𝟐) ] = sin[𝜋/3−(− 〖𝒔𝒊𝒏〗^(−𝟏)(𝟏/𝟐) )] = sin[𝜋/3+〖𝒔𝒊𝒏〗^(−𝟏)(𝟏/𝟐) ] = sin[𝜋/3+𝜋/𝟔] = sin〖𝜋/2〗 = 1 So, the correct answer is (d)
CBSE Class 12 Sample Paper for 2022 Boards (MCQ Based - for Term 1)
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CBSE Class 12 Sample Paper for 2022 Boards (MCQ Based - for Term 1)
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